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Exercise_2.java
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// Time Complexity :
// Best/Average Case: O(n log n) where n is the size of the array
// Worst Case: O(n^2) , when pivot is always the smallest or largest element)
// Space Complexity: O(log n) , due to recursion call
class QuickSort
{
/* This function takes last element as pivot,
places the pivot element at its correct
position in sorted array, and places all
smaller (smaller than pivot) to left of
pivot and all greater elements to right
of pivot */
void swap(int arr[],int i,int j){
//Your code here
int temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
int partition(int arr[], int low, int high)
{
//Write code here for Partition and Swap
int pivot = arr[high];
int i = low - 1;
for(int j = i+1 ;j < high; j++) {
//if element is smaller or equal to pivot, swap
if(arr[j] <= pivot) {
swap(arr, ++i, j);
}
}
// final swap with the pivot
swap(arr, i+1, high);
// returns partition index
return i+1;
}
/* The main function that implements QuickSort()
arr[] --> Array to be sorted,
low --> Starting index,
high --> Ending index */
void sort(int arr[], int low, int high)
{
// Recursively sort elements before
// partition and after partition
if(low < high){
int partIndex = partition(arr, low, high);
sort(arr, low , partIndex-1);
sort(arr, partIndex+1 ,high );
}
}
/* A utility function to print array of size n */
static void printArray(int arr[])
{
int n = arr.length;
for (int i=0; i<n; ++i)
System.out.print(arr[i]+" ");
System.out.println();
}
// Driver program
public static void main(String args[])
{
int arr[] = {10, 7, 8, 9, 1, 5};
int n = arr.length;
QuickSort ob = new QuickSort();
ob.sort(arr, 0, n-1);
System.out.println("sorted array");
printArray(arr);
}
}